|
= ' due to the azimuthal property = f (r)x = cos ![]() y = sin ![]() |
=
.
from the center of the map is
directly proportional to radial distance from the tangent
point. In the North polar aspect:
= (
/ 2 -
)R
= (
/ 2 +
)R and
=
-
Area element on sphere, given colatitude =
/ 2 - :ds = 2 R sin R d =
2 R² sin d![]() |
|
Corresponding element on map: ds =
2 rdr |
|
1, we want
:
A similar sign change applies if the south polar aspect is intended.
|
| Combined azimuthal equidistant (top) and equal-area (bottom) polar maps |
Calculating other aspects for azimuthal maps is possible applying coordinate transformations and rotations in space. However, the important equatorial aspect can be obtained in a more direct way, using two properties of triangles on a spherical surface.
|
Given A, B, C
angles on a spherical triangle's vertices, and
, , the corresponding angles between
edges connecting triangle vertices and
center O of sphere, |
|
| Law of sines: | sin A / =
sin B / =
sin C / ![]() |
|
| Law of cosines: | cos = cos
cos + sin sin
sin C |
|
On the equatorial
aspect, tangent point T lies on the intersection
of Equator and an arbitrary central meridian. The
projected point P marks a shaded triangle, whose
vertices define central angle
, latitude
and longitude
.

and
sin
,
= r =
R
x =
R cos
sin
/ sin 
y =
R sin
/
sin 
=
= 0, sin
= 0, x =
y = 0.
for
1:
x =
cos
=
cos
/ sin
sin 
y =
sin
=
sin
/ sin 

|
| Combined azimuthal equidistant (top) and equal-area (bottom) equatorial maps |