Two Aspects for Two Arbitrary Azimuthal Projections
General Polar Azimuthal Projections
The mathematical development of the azimuthal
orthographic projection is purely geometric. Even
though some azimuthal projections do not follow such a
perspective process, all can be reduced to a general pattern,
given the tangency point T:
 | |
Outlined projection plane tangent to sphere at point T |
|
θ = θ' due to the azimuthal property
ρ = f (r)
x = ρ cos θ
y = ρ sin θ |
For the North polar
aspect, θ = λ.
The Azimuthal Equidistant Projection
For the azimuthal
equidistant, an important projection for navigational
applications, distance ρ from the center of the map is
directly proportional to radial distance from the tangent
point. In the North polar aspect:
ρ = (π / 2 − φ)R
The austral aspect is just as easy, with
ρ = (π / 2 + φ)R and θ =
−λ
Lambert's Azimuthal Equal-area Projection
In the only projection
both azimuthal and equal-area,
created by Lambert and suitable for world maps,
distance from the center of the map is progressively reduced in
order to keep areal equivalence. Formulas follow from
basic integral calculus.
Area element on sphere, given colatitude Φ =
π / 2 − φ:
ds = 2πR sin Φ R dΦ =
2πR² sin Φ dΦ |
|
| Corresponding element on map: ds =
2πrdr |
|
For a given Φ1, we want ρ:
A similar sign change applies if the south polar aspect is
intended.
|
| Combined azimuthal equidistant (top)
and equal-area (bottom) polar maps |
The combined map shows both projections virtually identical at
latitudes above 70°N. Beyond that, parallels get
closer and closer together in Lambert's half, while remaining
equally spaced in the azimuthal equidistant portion. The
resulting areal difference is clearly visible in Antarctica.
General Equatorial Aspect for Azimuthal Maps
Calculating other aspects for azimuthal maps is possible
applying coordinate transformations and rotations in
space. However, the important
equatorial aspect can be
obtained in a more direct way, using two properties of
triangles on a spherical surface.
|
Given A, B, C
angles on a spherical triangle's vertices, and
α, β, γ the corresponding angles between
edges connecting triangle vertices and
center O of sphere, |
| Law of sines: |
sin A / α =
sin B / β =
sin C / γ |
| Law of cosines: |
cos γ = cos α
cos β + sin α sin β
sin C |
On the equatorial
aspect, tangent point T lies on the intersection
of Equator and an arbitrary central meridian. The
projected point P marks a shaded triangle, whose
vertices define central angle α, latitude φ
and longitude λ.

Just substituting results for cos θ and
sin θ,
ρ = r = αR
x = αR cos φ
sin λ / sin α
y = αR sin φ /
sin α
If λ = φ = 0, sin α = 0, x =
y = 0.
In equations for Lambert's equal-area azimuthal projection,
substitute α for Φ1:
x = ρ cos θ = ρ
cos φ / sin λ
sin α
y = ρ sin θ = ρ
sin φ / sin α
sin (a + b) = sin a
cos b + cos a sin b,
therefore sin 2a = 2 sin a
cos a
cos (a + b) = cos a
cos b − sin a
sin b; cos 2a =
cos2a − sin2a =
2 cos2a − 1, therefore
(cos 2a + 1) / 2 = cos2a

|
| Combined azimuthal equidistant (top)
and equal-area (bottom) equatorial maps |
Again, both projections are very similar near the tangent
point: the northern and southern portions of Africa join almost
seamlessly.
 |  |  |  |  |  | | www.progonos.com/furuti January 14, 2004 |
Copyright © 2001 Carlos A. Furuti